ECMA-334: 12.3.3.24 short circuit OR expressions
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12.3.3.24 || expressions
For an expression expr of the form expr-first || expr-second:
- The definite assignment state of v before expr-first is the same as the definite assignment state of v before expr.
- The definite assignment state of v before expr-second is definitely assigned if the state of v after expr-first is either definitely assigned or "definitely assigned after false expression". Otherwise, it is not definitely assigned.
- The definite assignment statement of v after expr is determined by:
- If the state of v after expr-first is definitely assigned, then the state of v after expr is definitely assigned.
- Otherwise, if the state of v after expr-second is definitely assigned, and the state of v after expr-first is "definitely assigned after true expression", then the state of v after expr is definitely assigned.
- Otherwise, if the state of v after expr-second is definitely assigned or "definitely assigned after false expression", then the state of v after expr is "definitely assigned after false expression".
- Otherwise, if the state of v after expr-first is "definitely assigned after true expression", and the state of v after expr-second is "definitely assigned after true expression", then the state of v after expr is "definitely assigned after true expression".
- Otherwise, the state of v after expr is not definitely assigned.
[Example: In the following code
class A { static void G(int x, int y) { int i; if (x >= 0 || (i = y) >= 0) { // i not definitely assigned } else { // i definitely assigned } // i not definitely assigned } }
the variable i is considered definitely assigned in one of the embedded statements of an if statement but not
in the other. In the if statement in method G, the variable i is definitely assigned in the second embedded
statement because execution of the expression (i = y) always precedes execution of this embedded
statement. In contrast, the variable i is not definitely assigned in the first embedded statement, since
x >= 0 might have tested true, resulting in the variable i's being unassigned. end example]